Web14 dec. 2024 · First approach: extract the dates from the variables you have and then subtract the dates. Code: gen int concuss_onset_date = dofc (concuss_onset) gen int episode_start_date = dofc (episode_start_dt) format *_date %td gen days_since_con = episode_start_date - concuss_onset_date Web26 apr. 2024 · That's like going to a library when you already have the answer in a book on your desk. create a new variable with only the (daily) date This is what dofc () does, which I referred you to, so all you need to do is use it in a generate command: Code: gen dailydate = dofc (datetime) format my date variable so I only see the date (not the time)

Stata tip 111: More on working with weeks - SAGE Journals

Web1 apr. 2024 · There is no Stata function dmy (), as you have found. mdy () is what is available for that specific purpose and it expects month day and year in exactly that order. But you can write the same example any other way you like that is legal. Here's one Code: . di %tdCY!ww daily ("1 April 2024", "DMY") 2024w13 WebThese functions convert dates and times recorded as strings to Stata dates. Stata dates are numbers that can be formatted so that they look like the dates you are familiar with. See[D] Datetime for an introduction to Stata’s date and time features. Quick start Convert strdate1, with dates such as "Tue January 25, 2013", to a numerically ... thickness probe

Stata FAQ: Stata 5: Creating date variables

Web17 apr. 2024 · But don't I need to inform Stata that 1982 is a 'year' via: Code: gen date36=year (year36) The variable indicating birthday (which will be used with the above … WebIn Stata version 10: gen date2 = date (date, "DMY") The mdy () function takes three numeric arguments (month, day, year) and converts them to a date variable. generate … thickness quotes